Quiz(50/100)
[tex] \: \: \: [/tex]
f'(x) = 3x² + 2x
f(1) = ..
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[tex] \: \: \: [/tex]
f'(x) = 3x² + 2x
f(1) = ..
Jawaban:
f(1) = 2
Penjelasan dengan langkah-langkah:
f'(x) = 3x² + 2x
cari f(x) menggunakan antiturunan
[tex] \rm f(x) = \begin{gathered} \int \rm f'(x) dx \end{gathered} [/tex]
[tex]\rm f(x) = \begin{gathered} \int \rm (3x^2+2x) dx \end{gathered} [/tex]
[tex] \rm = \frac{3}{2 + 1} {x}^{2 + 1} + \frac{2}{1 + 1} {x}^{1 + 1} + C [/tex]
[tex] \rm = \frac{3}{3} {x}^{3} + \frac{2}{2} {x}^{2} + C[/tex]
[tex] \rm = {x}^{3} + {x}^{2} + C [/tex]
f(x) = x³ + x²
f(1) = 1³ + 1²
f(1) = 1 + 1
f(1) = 2
[tex]____________[/tex]
koreksi
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